# std::chrono::year_month_weekday::operator sys_days, std::chrono::year_month_weekday::operator local_days

From cppreference.com
< cpp‎ | chrono‎ | year month weekday

constexpr operator std::chrono::sys_days () const noexcept; | (1) | (since C++20)
constexpr explicit operator std::chrono::local_days () const noexcept; | (2) | (since C++20)

Converts *this to a std::chrono::time_point representing the same date as this `year_month_weekday`.

1) If year().ok() && month().ok() && weekday().ok():

  - If index() == 0, returns a `sys_days` that represents the date 7 days prior to the first `weekday()` of the year and month.
  - Else, returns a `sys_days` that represents the date (index() - 1) * 7 days after the first weekday() of the year and month.

Otherwise, the returned value is unspecified.
2) Same as (1), but returns `local_days` instead of `sys_days`. Equivalent to local_days(sys_days(*this).time_since_epoch()).

### Example

Run this code

    #include <chrono>
    #include <iostream>
    using namespace std::chrono;

    int main()
    {
        constexpr auto ymwd{Tuesday[2]/11/2021};
        std::cout << ymwd << '\n';
        // convert from field-based to serial-based to add hours
        constexpr auto sd = sys_days{ymwd} + 24h;
        std::cout << sd << '\n';
        constexpr auto ymd = floor<days>(sd);
        static_assert(ymd == November/10/2021);
    }

Output:

    2021/Nov/Tue[2]
    2021-11-10 00:00:00

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