# std::launder

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< cpp‎ | utility

Defined in header `<new>` |  |
template< class T > constexpr T* launder( T* p ) noexcept; |  | (since C++17)

Devirtualization fence with respect to p. Returns a pointer to an object at the same address that p represents, while the object can be a new base class subobject whose most derived class is different from that of the original *p object.

Formally, given

- the pointer p represents the address `A` of a byte in memory
- an object x is located at the address `A`
- x is within its lifetime
- the type of x is the same as `T`, ignoring cv-qualifiers at every level
- every byte that would be reachable through the result is reachable through p (bytes are reachable through a pointer that points to an object y if those bytes are within the storage of an object z that is pointer-interconvertible with y, or within the immediately enclosing array of which z is an element).

Then std::launder(p) returns a value of type `T*` that points to the object x. Otherwise, the behavior is undefined.

The program is ill-formed if `T` is a function type or (possibly cv-qualified) void.

`std::launder` may be used in a core constant expression if and only if the (converted) value of its argument may be used in place of the function invocation. In other words, `std::launder` does not relax restrictions in constant evaluation.

### Notes

`std::launder` has no effect on its argument. Its return value must be used to access the object. Thus, it's always an error to discard the return value.

Typical uses of `std::launder` include:

- Obtaining a pointer to an object created in the storage of an existing object of the same type, where pointers to the old object cannot be reused (for instance, because either object is a base class subobject);
- Obtaining a pointer to an object created by placement `new` from a pointer to an object providing storage for that object.

The reachability restriction ensures that `std::launder` cannot be used to access bytes not accessible through the original pointer, thereby interfering with the compiler's escape analysis.

    int x[10];
    auto p = std::launder(reinterpret_cast<int(*)[10]>(&x[0])); // OK

    int x2[2][10];
    auto p2 = std::launder(reinterpret_cast<int(*)[10]>(&x2[0][0]));
    // Undefined behavior: x2[1] would be reachable through the resulting pointer to x2[0]
    // but is not reachable from the source

    struct X { int a[10]; } x3, x4[2]; // standard layout; assume no padding
    auto p3 = std::launder(reinterpret_cast<int(*)[10]>(&x3.a[0])); // OK
    auto p4 = std::launder(reinterpret_cast<int(*)[10]>(&x4[0].a[0]));
    // Undefined behavior: x4[1] would be reachable through the resulting pointer to x4[0].a
    // (which is pointer-interconvertible with x4[0]) but is not reachable from the source

    struct Y { int a[10]; double y; } x5;
    auto p5 = std::launder(reinterpret_cast<int(*)[10]>(&x5.a[0]));
    // Undefined behavior: x5.y would be reachable through the resulting pointer to x5.a
    // but is not reachable from the source

### Example

Run this code

    #include <cassert>
    #include <cstddef>
    #include <new>

    struct Base
    {
        virtual int transmogrify();
    };

    struct Derived : Base
    {
        int transmogrify() override
        {
            new(this) Base;
            return 2;
        }
    };

    int Base::transmogrify()
    {
        new(this) Derived;
        return 1;
    }

    static_assert(sizeof(Derived) == sizeof(Base));

    int main()
    {
        // Case 1: the new object failed to be transparently replaceable because
        // it is a base subobject but the old object is a complete object.
        Base base;
        int n = base.transmogrify();
        // int m = base.transmogrify(); // undefined behavior
        int m = std::launder(&base)->transmogrify(); // OK
        assert(m + n == 3);

        // Case 2: access to a new object whose storage is provided
        // by a byte array through a pointer to the array.
        struct Y { int z; };
        alignas(Y) std::byte s[sizeof(Y)];
        Y* q = new(&s) Y{2};
        const int f = reinterpret_cast<Y*>(&s)->z; // Class member access is undefined
                                                   // behavior: reinterpret_cast<Y*>(&s)
                                                   // has value "pointer to s" and does
                                                   // not point to a Y object
        const int g = q->z; // OK
        const int h = std::launder(reinterpret_cast<Y*>(&s))->z; // OK

        [](...){}(f, g, h); // evokes [[maybe_unused]] effect
    }

### Defect reports

The following behavior-changing defect reports were applied retroactively to previously published C++ standards.

DR | Applied to | Behavior as published | Correct behavior
--- | --- | --- | ---
LWG 2859 | C++17 | definition of reachable did not consider pointer arithmetic from pointer-interconvertible object | included
LWG 3495 | C++17 | `std::launder` might make pointer to an inactive member dereferenceable in constant expression | forbidden

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