# std::chrono::year_month_day_last::operator sys_days, std::chrono::year_month_day_last::operator local_days

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< cpp‎ | chrono‎ | year month day last

constexpr operator std::chrono::sys_days () const noexcept; | (1) | (since C++20)
constexpr explicit operator std::chrono::local_days () const noexcept; | (2) | (since C++20)

Converts *this to a std::chrono::time_point representing the same date as this `year_month_day_last`. This is equivalent to composing a `year_month_day` from `year()`, `month()` and `day()` and converting that `year_month_day` to the destination type.

1) Equivalent to std::chrono::sys_days (year()/month()/day()).
2) Equivalent to std::chrono::local_days (year()/month()/day()).

### Example

Run this code

    #include <array>
    #include <chrono>
    #include <iostream>
    #include <string_view>
    using namespace std::chrono;
    using namespace std::literals;

    int main()
    {
        constexpr std::chrono::year y{2023y};
        constexpr std::array quarters{"1st"sv, "2nd"sv, "3rd"sv, "4th"sv};
        constexpr auto mq{12 / 4}; // months per quarter

        std::cout << "In year " << static_cast<int>(y) << '\n';
        for (auto q = 1; q < 5; ++q)
        {
            const auto ls = y / std::chrono::month(q * mq) / Sunday[last];
            const auto ld = y / std::chrono::month(q * mq) / last;
            // subtract last Sunday from last day for day of week
            const auto index = (sys_days(ld) - sys_days(ls)).count();
            std::cout << "The " << quarters[q - 1] << " quarter ends on a "
                      << std::chrono::weekday(index) << '\n';
        }
    }

Output:

    In year 2023
    The 1st quarter ends on a Fri
    The 2nd quarter ends on a Fri
    The 3rd quarter ends on a Sat
    The 4th quarter ends on a Sun

### See also

operator sys_daysoperator local_days | converts to a std::chrono::time_point (public member function of `std::chrono::year_month_day`)

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