# std::chrono::year_month_day_last::year_month_day_last

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< cpp‎ | chrono‎ | year month day last

constexpr year_month_day_last( const std::chrono::year & y, const std::chrono::month_day_last & mdl ) noexcept; |  | (since C++20)

Constructs a `year_month_day_last` object storing the year y and the month mdl.month(). The constructed object represents the last day of that year and month.

### Notes

A `year_month_day_last` can also be created by combining a std::chrono::year_month with std::chrono::last using operator/.

### Example

Run this code

    #include <chrono>
    #include <iostream>

    int main()
    {
        std::cout << "All last days of months of a given year:\n";

        constexpr std::chrono::year year{2021};

        for (int i{1}; i <= 12; ++i)
        {
            const std::chrono::month_day_last mdl{std::chrono::month(i) / std::chrono::last};
            const std::chrono::year_month_day_last ymdl{year, mdl};
            std::cout << ymdl << " day: " << ymdl.day() << '\n';
        }
    }

Possible output:

    All last days of months of a given year:
    2021/Jan/last day: 31
    2021/Feb/last day: 28
    2021/Mar/last day: 31
    2021/Apr/last day: 30
    2021/May/last day: 31
    2021/Jun/last day: 30
    2021/Jul/last day: 31
    2021/Aug/last day: 31
    2021/Sep/last day: 30
    2021/Oct/last day: 31
    2021/Nov/last day: 30
    2021/Dec/last day: 31

### See also

operator/ (C++20) | conventional syntax for Gregorian calendar date creation (function)

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